The sum of three consecutive natural numbers each
divisible by 5, is 225. The largest among them is
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since each number is divisible by 5 and are consecutive.
so the number are X , X + 5 and X + 10
A/Q
X + X + 5 + X + 10 = 225
3x + 15 = 225
3x = 210
x = 70
So the number are
X = 70
X + 5 = 75
X + 10 = 80
The largest among them is 80 .
So, the required answer is 80.
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