The sum of three consecutive natural numbers is 114 find that number
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let the 1st no. be X
2nd no.= X+1
3rd no.=X+2
ATQ
X+X+1+X+2=114
3X+3=114
3X=111
X=111/3
X=37
Hence
1st no.=37
2nd no.=38
3rd no.=39
2nd no.= X+1
3rd no.=X+2
ATQ
X+X+1+X+2=114
3X+3=114
3X=111
X=111/3
X=37
Hence
1st no.=37
2nd no.=38
3rd no.=39
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