The sum of three consecutive natural numbers is 114 find the number.
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Let 1st number be X, 2nd number be X+1 and 3rd number be X+2
then....
X+X+1+X+2 = 114
3x+3 = 114
3x = 111
X = 111/3
X = 37
X+1 = 38
X+2 = 39
Hope it helps
Answered by
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Answer:
this is wrong
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