Question

the sum of three consecutive natural numbers is 114 find the numbers

Answer 1

let one of the number be x
x+x+1+x+2=114
3x+3=114
3(x+1)=114
x+1=114÷3
x+1=38
x=38-1=37
please mark as brainlist

Answer 2

one number =  x

other number = x+1

last number = x+2

sum = 114


according to the sum

 x+x+1+x+2 = 114

3x+3 = 114

3x= 114-3

x = 111 / 3
 
x= 37,x+1 = 38,x+2 = 39

hope it helps