Question

the sum of three consecutive natural numbers is 114.find the numbers

Answer 1

Let natural no. Be n,n+1,n+2
Therefore
n+n+1+n+2=114
3N=111
N=37
No.s are 37,38,39

Answer 2

Answer:

37, 38, 39

Step-by-step explanation:

Let an integer be x.

The two other consecutive integers:

x + 1

x + 2

--------------------------------

Integer 1: x

Integer 2: x + 1

Integer 3: x + 2

According to Question,

            (x) + (x + 1) + (x + 2) = 114

      =>   x + x + 1 + x + 2 = 114

      =>   3x + 3 = 114

      =>   3x = 114 - 3

      =>   3x = 111

      =>    x = 111/3

      =>    x = 37

Now,

1st Integer = x = 37

2nd Integer = x + 1 = 37 + 1 = 38

3rd Integer = x + 2 = 37 + 2 = 39

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