the sum of three consecutive natural numbers is 114. find the number
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x+x+1+x+2=114
3x+3=114
3(x+1)=114
x+1=38
x=37
The numbers are x,x+1,x+2
=37,38,39
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3x+3=114
3(x+1)=114
x+1=38
x=37
The numbers are x,x+1,x+2
=37,38,39
HOPE THIS HELPS YOU BUDDY ✌️
IF YOU LIKE IT PLEASE MARK IT AS BRAINLIEST
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Let the three consecutive numbers =x+1,x+2 and x+3
x+1+x+2+x+3=114
3x+6=114
3x=114-6
3x=108
x=108/3
x=36
Numbers =x+1=>36+1=37
=x+2=>36+2=38
=x+3=>36+3=39
x+1+x+2+x+3=114
3x+6=114
3x=114-6
3x=108
x=108/3
x=36
Numbers =x+1=>36+1=37
=x+2=>36+2=38
=x+3=>36+3=39
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