The sum of three consecutive natural numbers is 144. Find the numbers.
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Answer:
Let the no.s =x, x+1,x+2
Acc.to the statement
X+x+1+x+2=144
3x + 3= 144
3x=144-3
3x=141
X=141/3
X=47
The no.s are = 47,48,49
Step-by-step explanation:
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Let the no be x,x+1,x+2
X+[x+1]+[x+2]=144
3x +3 =144
3x=144-3
X=141/3
X=47
Putting value of x in
X+1=47+1=48
X+2=47+2=49
Three consecutive no are 47,48 and 49
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X+[x+1]+[x+2]=144
3x +3 =144
3x=144-3
X=141/3
X=47
Putting value of x in
X+1=47+1=48
X+2=47+2=49
Three consecutive no are 47,48 and 49
Mark me as a brainlist !!!!
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