Question

The sum of three consecutive natural numbers is 225. Find the numbers

Answer 1

$\sf\red{\underline{\underline{Answer:}}}$

$\sf{Numbers \ are \ 74, \ 75 \ and \ 76.}$

$\sf\orange{Given:}$

$\sf{\implies{Sum \ of \ three \ consecutive \ natural}}$

$\sf{numbers \ is \ 225.}$

$\sf\pink{To \ find:}$

$\sf{The \ numbers.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Let \ the \ three \ consecutive \ numbers \ be}$

$\sf{(n-1), \ n \ and \ (n+1)}$

$\sf{According \ to \ the \ given \ condition.}$

$\sf{(n-1)+n+(n+1)=225}$

$\sf{\therefore{3n=225}}$

$\sf{\therefore{n=\frac{225}{3}}}$

$\boxed{\sf{\therefore{n=75}}}$

$\sf{Numbers \ are:}$

$\sf{(n-1)=75-1=74,}$

$\sf{n=75,}$

$\sf{(n+1)=75+1=76.}$

$\sf\purple{\tt{\therefore{Numbers \ are \ 74, \ 75 \ and \ 76.}}}$

Answer 2

Given ,

The sum of three consecutive natural numbers is 225

Let , the three consecutive natural numbers be x , x + 1 , x + 2

According to the question ,

$\sf \Rightarrow x + x + 1 + x + 2 = 225 \\ \\\sf \Rightarrow 3x + 3 = 225 \\ \\\sf \Rightarrow 3x = 222 \\ \\\sf \Rightarrow x = \frac{222}{3} \\ \\\sf \Rightarrow x = 74$

$\therefore \sf \bold{ \underline{The \: numbers \: are \: 74 \: , \: 75 \: and \: 76 }}$