Question

the sum of three consecutive natural numbers is 36. what are the numbers?

Plz help me.... Its very urgent.. ​

Answer 1

Answer:

First number: 11

Second number: 11+1=12

Third number: 11+2=13

Step-by-step explanation:

First number: x

Second number: x+1

Third number: x+2

ATQ

x+(x+1)+(x+2)=36

3x+3=36

3x=36-3

x=33/3

x=11

Hopefully it will help.....

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Answer 2

Step-by-step explanation:

let ist = x

ii = x+1 because the consecutive number is one more than the previous

iii =x+1+1

x+x+1+x+1+1=36

3x+3=36

3x=36-3=33

x=33/3

x=11

I was x and x is 11

ii was x+1 so 11+1=12

ii was x+1+1 so 11+1+1=13

verification=11+12+13=36

*Proved*