Question

The sum of three consecutive natural numbers is 45. Which are the numbers?​

Answer 1

Answer:

Let the first number be n, therefore 2 consecutive numbers would be, n + 1 and n + 2

It is given that there sum is 45.

Now,

$\rm \implies\:n + n + 1 + n + 2 = 45 \\ \rm \implies\:3n + 3 = 45 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \rm \implies\: 3n = 45 - 3 = 42 \: \: \: \: \: \: \: \: \: \: \: \: \\ \rm \implies\:n = \frac{42}{3} = 14 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Since, n = 45, therefore

$\rm \implies \: n + 1 = 14 + 1 = 15 \: \\ \rm \implies\:n + 2 = 1 + + 2 = 16$

Therefore, the three consecutive numbers are 14, 15 and 16 respectively.

Hope it helps you

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