Question

the sum of three consecutive number divisible by 3 is 108.find these numbers.

Answer 1

Answer:

As the numbers are consecutive let the numbers be x,x+1,x+2.

now by given condition :-

x+x+1+x+2/3=108

3x+3/3=108

3x=321

x=107

so numbers are

107,108,109

hope it helps.

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