Question

the sum of three consecutive number in AP is 27 and their product is 504 find them

Answer 1

let the three consecutive term of the ap is a,a+d,a-d by th solving the 1st equation be get the a equal to 9 and according to second condition be get d
equal to 5 and by solving this be get
we get the three consecutive term of an AP is 4,9 and 14

Answer 2

Here is your solution

Given :-

sum of three consective term of ap is 27.

their product is 504

Let
The three numbers be a-d , a ,a+d.

A/q

a-d+a+a+d=27
3a=27
a=27/3
a=9

(a-d)×a×(a+d)=504

(a^2-d^2)a=504

(9^2-d^2)9=504

81-d^2 = 504/9

81-d^2= 56

d^2 = 81-56
d^2 = 25

d= + -5

If d=+5
Terms of A.p are 4,9,14✔

If d=-5
Terms of AP are 14,9,4✔

Thanks