Question

The Sum
of
three consecutive
number is 123 . Find the three
Integers.​

Answer 1

Answer:

Let the 1st number as y.

Let the 2nd number as y+1

Let the 3rd number as y+2.

Now,

$y + y + 1 + y + 2 = 123 \\ 3y + 3 = 123 \\ 3y = 123 - 3 \\ 3y = 120 \\ y = 40$

Hence, the 1st number is 40

the 2nd number is (40+1)= 41

the 3rd number is (40+2) = 42

Verification:

40+41+42=123