the sum of three consecutive number is 15,then the numbers are
Answers
Answer:
Let , the numbers be - x , ( x + 1) , ( x + 2)
ATQ
________
x + ( x + 1 ) + ( x + 2 ) = 15
x + x + 1 + x + 2 = 15
3x + 3 = 15
3 ( x + 1 ) = 15
( x + 1 ) = 15 / 3
( x + 1 ) = 5
x = 5 - 1
x = 4
so , x= 4
( x + 1 ) = ( 4 + 1 ) = 5
( x + 2 ) = ( 4+ 2 ) = 6
. ° . The consequtive numbers are 4 , 5 , 6 .
Answer:
Let's have the first integer be n . The second integer, since it is right after the first, will be n+1 . The third integer, since it is right after the second, will be (n+1)+1=n+2 .
The illustrate this concept, consider the integers
1 , 2 and 3 ,2 is one more than 1 , or in other words 2=1+1 . Same for 3 , except 3 is two more than 1 , so 3=1+2 . Since the integers are consecutive, each is one more than the last.
We're told that the sum of our three integers is 15 . Therefore,
n+(n+1)+(n+2)=15
Solving this equation is pretty straightforward:
3n+3=15
3n=12
n=12/3
n=4.
That means our first integer is 4 . Our second integer is
4+1 , or 5 , and our third integer is 5+1 , or 6 . Our answer is confirmed because 4+5+6=15 .
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