Math, asked by pavni2847, 8 months ago

the sum of three consecutive number is 15,then the numbers are​

Answers

Answered by Anonymous
2

Answer:

Let , the numbers be - x , ( x + 1) , ( x + 2)

ATQ

________

x + ( x + 1 ) + ( x + 2 ) = 15

x + x + 1 + x + 2 = 15

3x + 3 = 15

3 ( x + 1 ) = 15

( x + 1 ) = 15 / 3

( x + 1 ) = 5

x = 5 - 1

x = 4

so , x= 4

( x + 1 ) = ( 4 + 1 ) = 5

( x + 2 ) = ( 4+ 2 ) = 6

. ° . The consequtive numbers are 4 , 5 , 6 .

Answered by sanjanayadav10
2

Answer:

Let's have the first integer be n . The second integer, since it is right after the first, will be n+1 . The third integer, since it is right after the second, will be (n+1)+1=n+2 .

The illustrate this concept, consider the integers

1 , 2 and 3 ,2 is one more than 1 , or in other words 2=1+1 . Same for 3 , except 3 is two more than 1 , so 3=1+2 . Since the integers are consecutive, each is one more than the last.

We're told that the sum of our three integers is 15 . Therefore,

n+(n+1)+(n+2)=15

Solving this equation is pretty straightforward:

3n+3=15

3n=12

n=12/3

n=4.

That means our first integer is 4 . Our second integer is

4+1 , or 5 , and our third integer is 5+1 , or 6 . Our answer is confirmed because 4+5+6=15 .

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