the sum of three consecutive number is 156 find the number which is a multiple of 3 out of these numbers
Answers
Answered by
3
heya friend here's ur answer :-)
Let the first number be X ,
then the second and third number are-X+1,X+2
Given,
X+(X+1)+(X+2)=156
3X+3=156
3(X+1)=156
X+1=156/3=52
X=52-1=51. (that is the first number)
X+1=52. (that is the second number)
X+2=53. (that is the third number)
A/Q,
51 is the multiple of 3 out if these numbers.
hope it helps
Let the first number be X ,
then the second and third number are-X+1,X+2
Given,
X+(X+1)+(X+2)=156
3X+3=156
3(X+1)=156
X+1=156/3=52
X=52-1=51. (that is the first number)
X+1=52. (that is the second number)
X+2=53. (that is the third number)
A/Q,
51 is the multiple of 3 out if these numbers.
hope it helps
Answered by
7
Here is your solution
Given :-
The sum of three consecutive numbers is 156
Let consecutive number be x ,x+1,x+2
A/q
=>x+(x+1)+(x+2)= 156
=>3x+3=156
=>3x=156-3
=>3x = 153
=>x=51
The three consecutive numbers is
x = 51
x +1 = 51+1 = 52
x+2 = 51+2 = 53
The three consecutive numbers is 51,52,53
Hence
52 is multiple of 13✔
Hope it helps you
Given :-
The sum of three consecutive numbers is 156
Let consecutive number be x ,x+1,x+2
A/q
=>x+(x+1)+(x+2)= 156
=>3x+3=156
=>3x=156-3
=>3x = 153
=>x=51
The three consecutive numbers is
x = 51
x +1 = 51+1 = 52
x+2 = 51+2 = 53
The three consecutive numbers is 51,52,53
Hence
52 is multiple of 13✔
Hope it helps you
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