the sum of three consecutive number is 276. Find the number
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Answered by
13
Hey there!!
The solution for the question is..
Let the three consecutive numbers be x, x+1, x +2
Sum of three consecutive numbers is 276.
So, x +( x+1 )+( x+ 2 )= 276
x + x + 1 + x + 2 = 276
3x + 3 = 276
3x = 276 - 3
3x = 273
3x / 3 = 273/3
x = 91
x = 91
x + 1 = 91 + 1 = 92
x + 2 = 91 + 2 = 93
Hence the three consecutive numbers are 91,92,93.
This is the answer.
The solution for the question is..
Let the three consecutive numbers be x, x+1, x +2
Sum of three consecutive numbers is 276.
So, x +( x+1 )+( x+ 2 )= 276
x + x + 1 + x + 2 = 276
3x + 3 = 276
3x = 276 - 3
3x = 273
3x / 3 = 273/3
x = 91
x = 91
x + 1 = 91 + 1 = 92
x + 2 = 91 + 2 = 93
Hence the three consecutive numbers are 91,92,93.
This is the answer.
Answered by
6
let the number are x,x+1,x+2
X+(X+1)+(X+2)=276
3X+3=276
X=273/3=91
so the number are 91,92 and 93
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