the sum of three consecutive number is 36 find the number
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0
x, x+2 ,x+4 then are consecutive numbers
Answered by
1
let the numbers be ,
X
X+1
X+2
According to the question,
x + (x+1) + (x+2) =36
3x+3=36
3x=36-3
3x=33
x=33\3
X=11
therefore,
x=11
x+1=11+1
=12
x+2=11+2
=13
X
X+1
X+2
According to the question,
x + (x+1) + (x+2) =36
3x+3=36
3x=36-3
3x=33
x=33\3
X=11
therefore,
x=11
x+1=11+1
=12
x+2=11+2
=13
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