The sum of three consecutive number is 36find the number
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Given that sum of consecutive integers is 36.
Let the sum of consecutive integers be x , x + 1, x + 2.
x + x + 1 + x + 2 = 36
3x + 3 = 36
3x = 33
x = 11.
Therefore the Numbers are 11,12 and 13.
Hope this helps!
Let the sum of consecutive integers be x , x + 1, x + 2.
x + x + 1 + x + 2 = 36
3x + 3 = 36
3x = 33
x = 11.
Therefore the Numbers are 11,12 and 13.
Hope this helps!
Answered by
0
solutions:-
Let first no be X
second no be X+1
Third no be X+2
Given:-
The sum of three consecutive numbers is 36
A/q
X + X + 1 + X +2 = 36
=> 3x +3 = 36
=> 3x = 36 - 3
=> 3x = 33
=> X = 11
number are 11,12,13
Thanks ❣️
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