Question

the sum of three consecutive number mutiply of 11 is 468 find these mutiples​

Answer 1

Answer:

Step-by-step explanation:

★ In the Question there is 462 not 468

Let us take the first number as 11(C-1)

First consecutive number that is a multiple of 11 is 11C

Second consecutive number that is a multiple of 11 is 11(C + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11C + 11(C – 1) + 11(C + 1) = 468

11C + 11(C – 1) + 11(C + 1) = 468

33C = 468

C = 14

By substituting C = 14 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 154 , 143 and 165

Answer 2

Step-by-step explanation:

x+x+1+x+2=468

3x+3=468

3x=465

x=465/3

x=155

Therefore, x+1=156

x+2=157

I hope the answer will help you mate

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