Question

THE SUM OF THREE CONSECUTIVE NUMBERS IS 10 MORE THAN TWICE THE SMALLEST OF INTEGERS

Answer 1

Answer:

7,8,9

Step-by-step explanation:

x+x+1+x+2=(2*x)+10

3x+3=2x+10

3x-2x=10-3

x=7

x ,x+1, x+2=    7,8,9

Answer 2

Answer:

Step-by-step explanation:

Let x, x+1, x+2 be the numbers

So

x+x+1+x+2 = 2x+10

3x+3 =2x+10

x = 7

So the required answer is 7, 8, 9