the sum of three consecutive numbers is 120 find the numbers
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Let the three consecutive numbers be x, x+1, x+2
x+x+1+x+2=120
3x+3=120
3x=120-3
3x=117
x=117/3
x=39
Numbers are 39,40,41
x+x+1+x+2=120
3x+3=120
3x=120-3
3x=117
x=117/3
x=39
Numbers are 39,40,41
krishna3666:
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Answered by
2
Ans: Let the consecutive numbers be x , x+1 and x +2
sum:-
=> x+ x+1 +x +2 =120
=> 3x +3=120
=> 3x = 117
=>x = 39
Therefore, numbers are 39, 40 , 41
Hope it helps...!!
sum:-
=> x+ x+1 +x +2 =120
=> 3x +3=120
=> 3x = 117
=>x = 39
Therefore, numbers are 39, 40 , 41
Hope it helps...!!
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