Question

The sum of three consecutive numbers is 129.what is the smallest of the three numbers

Answer 1

Answer:42

Step-by-step explanation:let the numbers be x,x+1,x+2

X+x+1+x+2=129

3x+3=129

3x=129-3

X=126/3

X=42

So, x+1=42+1

=43

X+2=42+2

=44

Since the three consecutive numbers are 42,43,44

Therefore the smallest number is 42.