The sum of three consecutive numbers is 132. Find the square of the largest number.
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Answer:
let number be x and its positive square root be
√x
x + root of x = 132
root of x can be written as,
x/x2
= x+ (x/x2)
= (x3 + x) / x2
= x(x2 + 1) / x2
= (x2 + 1) / x
132 = (x2+1) / x
132x = x2 + 1
x2 - 132x + 1 = 0
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