The sum of three consecutive numbers is 192 .find them.
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Answer:
Numbers are 63,64 and 65
Explanation:
let the 3 consecutive numbers be
x,(x+1) and (x+2)
given
x+(x+1)+(x+2)=192
3x=192-3=189
so,x=189/3=63
so numbers are, x=63,.
(x+1)=63+1=64
(x+2)=63+2=65
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