Question

the sum of three consecutive numbers is 3000.the smallest of these number is​

Answer 1

Step-by-step explanation:

Let the three consecutive numbers be x, x+1 and x+2

According to the question

sum of consecutive numbers=3000

=> x+x+1+x+2=3000

3x+3=3000

3(x+1)=3(1000)

x=999

Hence, the numbers are 999, 1000 and 1001

And the smallest number is 999

:)

Answer 2

Step-by-step explanation:

Hope it will help you out