Question

The sum of three consecutive numbers is 36 . What are the smallest of these numbers

Answer 1

Let the consecutive numbers be x, x +1, x + 2

ATQ
$x + x + 1 + x + 2 = 36 \\ 3x + 3 = 36 \\ 3x = 33 \\ x = 11$
Therefore the smallest number is 11

Answer 2

Let the 3 consecutive numbers be x,(x+1) and (x+2)

Sum of these numbers is 36

x+(x+1)+(x+2)=36

3x+3=36

3x= 33

x= 11

The 3 numbers are 11,12 and 13

Therefore ,the smallest number is 11