Question

The sum of three consecutive numbers is 63. Find the
numbers.

Answer 1

In context to question asked,

We have to determine the value of three numbers.

As per question,

It is given that,

Sum of three consecutive numbers is 63.

So, let the numbers be $x,(x+1),(x+2)$

So, from the condition given in the question,

We can rewrite it as,

$x+(x+1)+(x+2) = 63\\=>3x+3 =63\\=>3x = 63-3 \\=>3x = 60\\=>x = \frac{60}{3}\\=>x = 20$

Hence, value of the numbers will be following,

$x = 20\\(x+1) = (20+1) = 21\\(x+2) = (20+2) = 22$

Answer 2

Here it is given that the sum of 3 consecutive numbers is 63.

Let us assume the first number to be x, then the next two numbers will be  x+1 and x + 2

So, x + x + 1 + x + 2 = 63

                    3x + 3 = 63

                            3x = 60

                             x = 60 / 3

                             x = 20

So, x + 1 = 20 + 1

              = 21

x + 2 = 20 + 2

       = 22

Hence, the three numbers will be 20, 21 and 22