Question

The sum of three consecutive numbers is equal to 21. The equation to solve this problem is​

Answer 1

Answer:

Let one number be x.

Then, the other number will be x+2.

The third number = x+2+2=x+4

It is given that their sum is 21.

So, x+(x+2)+(x+4)=21

3x+6=21

3x=15

x=5

and x+2=7

x+4=9.

Answer 2

Answer:

Solution:

Let, the three numbers be (x - 1), x and (x + 1) .

According to the given condition.

(x - 1) + x + (x + 1) = 21

=> x = 7

Therefore, numbers are 6, 7 and 8.