the sum of three consecutive numbers of an ap is 2 and their product is 4 find them
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Step-by-step explanation:
Let 3 no. be a-d, a, a+ d
A-d+a+a-d = 2
3a = 2 , a = 2/3
A×(a+d) × (a-d) = 4
(2/3)× a² - d² = 4
2/3(4/9 - d²) = 4
4/9 - d² = 4×3/2
4/9 - d² = 6
4/9-6 = d²
= /-25/3 = d
And this is not possible
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