Question

the sum of three consecutive odd integers is 39 find the smallest number​

Answer 1

Answer:

let first number b e x therefore second number x + 2 third number b x + 4

now according to question

X + X + 2 + X + 4 is equal to 39

3x + 6= 39

3x is equal to 39 -6

x is equal to 11

now x is equal to 11 x + 2 is equal to 13 x + 4 is equal to 15 smallest one is 11

Answer 2

(x),(x+2),(x+4)..........

x+x+2+x+4=39

3x+6=39

3x=39-6

3x=33

x=11