The sum of three consecutive odd integers is 63. find the largest
Answers
Consecutive odd integers are odd integers which follow one another and the difference between two odd numbers is 2.
Let the first odd integer be x.
The second = x + 2
The third = x + 2 + 2 = x + 4
The sum of the three numbers is :
x + x + 2 + x + 4 = 3x + 6
We equate this to 63.
3x + 6 = 63
3x = 63 - 6
3x = 57
x = 57/3
x = 19
The largest is the third number and is given by :
19 + 4 = 23
Answer : 23
Hi,
Here is your answer,
The first odd integer be y
The second odd integer be = y + 2
The third odd integer be = y + 2 + 2 = y + 4
The sum of the three numbers is :
→ y + y + 2 + y + 4 = 3 y + 6
Given three consecutive odd integer is 63.
→ 3 y + 6 = 63
→ y = 63 - 6
→ 3 y = 57
→ y = 57/3
→ y = 19
The largest odd integer value is
→ 19 + 4 = 23
Required solution is 23
Hope it helps you !
Hi,
Here is your answer,
The first odd integer be y
The second odd integer be = y + 2
The third odd integer be = y + 2 + 2 = y + 4
The sum of the three numbers is :
→ y + y + 2 + y + 4 = 3 y + 6
Given three consecutive odd integer is 63.
→ 3 y + 6 = 63
→ y = 63 - 6
→ 3 y = 57
→ y = 57/3
→ y = 19
The largest odd integer value is
→ 19 + 4 = 23
Required solution is 23
Hope it helps you !
Hi,
Here is your answer,
The first odd integer be y
The second odd integer be = y + 2
The third odd integer be = y + 2 + 2 = y + 4
The sum of the three numbers is :
→ y + y + 2 + y + 4 = 3 y + 6
Given three consecutive odd integer is 63.
→ 3 y + 6 = 63
→ y = 63 - 6
→ 3 y = 57
→ y = 57/3
→ y = 19
The largest odd integer value is
→ 19 + 4 = 23
Required solution is 23
Hope it helps you !
Hi,
Here is your answer,
The first odd integer be y
The second odd integer be = y + 2
The third odd integer be = y + 2 + 2 = y + 4
The sum of the three numbers is :
→ y + y + 2 + y + 4 = 3 y + 6
Given three consecutive odd integer is 63.
→ 3 y + 6 = 63
→ y = 63 - 6
→ 3 y = 57
→ y = 57/3
→ y = 19
The largest odd integer value is
→ 19 + 4 = 23
Required solution is 23
Hope it helps you !