Math, asked by remam9544, 1 year ago

The sum of three consecutive odd integers is 63. find the largest

Answers

Answered by santy2
5

Consecutive odd integers are odd integers which follow one another and the difference between two odd numbers is 2.

Let the first odd integer be x.

The second = x + 2

The third = x + 2 + 2 = x + 4

The sum of the three numbers is :

x + x + 2 + x + 4 = 3x + 6

We equate this to 63.

3x + 6 = 63

3x = 63 - 6

3x = 57

x = 57/3

x = 19

The largest is the third number and is given by :

19 + 4 = 23

Answer : 23

Answered by Anonymous
5

Hi,

Here is your answer,

The first odd integer be y

The second odd integer be = y + 2

The third odd integer be = y + 2 + 2 = y + 4

The sum of the three numbers is :

→ y + y + 2 + y + 4 = 3 y + 6

Given three consecutive odd integer is 63.

→ 3 y + 6 = 63

→ y = 63 - 6

→ 3 y = 57

→ y = 57/3

→ y = 19

The largest odd integer value is

→ 19 + 4 = 23

Required solution is 23

Hope it helps you !

Answered by Anonymous
4

Hi,

Here is your answer,

The first odd integer be y

The second odd integer be = y + 2

The third odd integer be = y + 2 + 2 = y + 4

The sum of the three numbers is :

→ y + y + 2 + y + 4 = 3 y + 6

Given three consecutive odd integer is 63.

→ 3 y + 6 = 63

→ y = 63 - 6

→ 3 y = 57

→ y = 57/3

→ y = 19

The largest odd integer value is

→ 19 + 4 = 23

Required solution is 23

Hope it helps you !


locomaniac: how do you give three answers?
locomaniac: four*
Anonymous: Well it's a bug. :-/
Answered by Anonymous
4

Hi,

Here is your answer,

The first odd integer be y

The second odd integer be = y + 2

The third odd integer be = y + 2 + 2 = y + 4

The sum of the three numbers is :

→ y + y + 2 + y + 4 = 3 y + 6

Given three consecutive odd integer is 63.

→ 3 y + 6 = 63

→ y = 63 - 6

→ 3 y = 57

→ y = 57/3

→ y = 19

The largest odd integer value is

→ 19 + 4 = 23

Required solution is 23

Hope it helps you !

Answered by Anonymous
6

Hi,

Here is your answer,

The first odd integer be y

The second odd integer be = y + 2

The third odd integer be = y + 2 + 2 = y + 4

The sum of the three numbers is :

→ y + y + 2 + y + 4 = 3 y + 6

Given three consecutive odd integer is 63.

→ 3 y + 6 = 63

→ y = 63 - 6

→ 3 y = 57

→ y = 57/3

→ y = 19

The largest odd integer value is

→ 19 + 4 = 23

Required solution is 23

Hope it helps you !

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