the sum of three consecutive odd intergers is 189 , what are the intergers?
please don't answer randomly it will make others think my questions already answerred :(
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Answer:
Lets call the first number x.
Then the next ODD number would be x+2.
The last would be x+4.
So x+(x+2)+(x+4)=189.
Combine all the x's and other numbers:
3x+6=189
solve for x:
(subtract 6 from both sides)---> 3x=183
(divide both sides by 3) ---> x=61
so the three numbers are 61, 63, 65.
check if it works:
61+63+65=189
THE INTEGERS ARE 61,63,65
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