The sum of three consecutive odd no. Is 63. Find the number that is 18 more than the second number
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Answered by
3
Step-by-step explanation:
three no. are : a-d ,a, a+d
a-d+a+a+d= 63
3a=63
a=21
no. is 18 more than second no. = 21+18
=39
Answered by
1
Answer:
40
Step-by-step explanation:
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