The sum of three consecutive odd nubets is 33.what are the numbers
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Answered by
2
Let the three consecutive nos. are x-1 , x and x+1
a/q x-1+x+x+1=33
3x=33. 1and-1 are canclled
so x=11
Therfore the numbers are,10 11 and 12
a/q x-1+x+x+1=33
3x=33. 1and-1 are canclled
so x=11
Therfore the numbers are,10 11 and 12
Answered by
2
let the number as X ; X+2; X+4
X +X+2X+4
== 3X+6 = 33
==3X = 33-6
==3X = 27
==X = 27÷3
==X = 9
so the numbers are 9 9+2 9+4
====== 9 ; 11 ; 13
X +X+2X+4
== 3X+6 = 33
==3X = 33-6
==3X = 27
==X = 27÷3
==X = 9
so the numbers are 9 9+2 9+4
====== 9 ; 11 ; 13
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