the sum of three consecutive odd number is 129 find the biggest number
Answers
Answered by
7
let the three consecutive numbers be x, X + 2, X + 4
as their sum is 129 we conclude
x+x+2+x+4=129
3x+6=129
3x=129-6
3x=123
therefore x=123/3
x=41
this is the answer
as their sum is 129 we conclude
x+x+2+x+4=129
3x+6=129
3x=129-6
3x=123
therefore x=123/3
x=41
this is the answer
Answered by
2
Solution :-
Let,
The first odd integer be:x
Then the second odd integer is:-
x+2
Then the third odd integer is:-
x+2+2=x+4
Sum of three consecutive odd numbers = 129
A/q
(x)+(x+2)+(x+4)= 129
3x+6= 129
3x= 129-6
3x= 123
x= 41
now
The first integer is: x= 41
The second integer is: x+2=19+2 = 43
The third integer is: x+4=19+4= 45
Biggest number is 45
Hope it helps you
Let,
The first odd integer be:x
Then the second odd integer is:-
x+2
Then the third odd integer is:-
x+2+2=x+4
Sum of three consecutive odd numbers = 129
A/q
(x)+(x+2)+(x+4)= 129
3x+6= 129
3x= 129-6
3x= 123
x= 41
now
The first integer is: x= 41
The second integer is: x+2=19+2 = 43
The third integer is: x+4=19+4= 45
Biggest number is 45
Hope it helps you
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