Question

the sum of three consecutive odd number is 20 more than the first number among 3. what is the middle number?​

Answer 1

Answer:

The middle number is 9.

Step-by-step explanation:

Let the three consecutive integers be, m, m + 2 and m + 4.

It is provided that the sum of these three numbers is 20 more than the first number, i.e.

$m+(m+2)+(m+4)=m+20\\3m+6=m+20\\2m=14\\m=7$

The consecutive odd integers are:

m = 7

m + 2 = 7 + 2 = 9

m + 4 = 7 + 4 = 11

Thus, the middle number is 9.