The sum of three consecutive odd number is 21 find number
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let the no be x+1 x+3 x+5
x+x+x+1+3+5= 21
3x+9=21
3x= 21-9= 12
x=12÷3
x= 4
so the answer is x+1 4+1 = 5, x+3 = 4+3 = 7, x+5 = 4+5=9.
x+x+x+1+3 = 21
3x+4=21
3x= 21-4
3x=
x+x+x+1+3+5= 21
3x+9=21
3x= 21-9= 12
x=12÷3
x= 4
so the answer is x+1 4+1 = 5, x+3 = 4+3 = 7, x+5 = 4+5=9.
x+x+x+1+3 = 21
3x+4=21
3x= 21-4
3x=
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