Question

The sum of three consecutive odd number is 213, find the numbers. ​

Answer 1

${\boxed{\huge{\mathfrak{\red{A}{\green{N}{S}{\orange{W}{\pink{E}{\purple{R}}}}}}}}}$

Sum of three consecutive numbers can be expressed as -

n + (n+1) + (n+2)

= 3n+3

For given problem expression can be written as -

3n + 3 = 213

3n = 213 - 3

3n = 210

n=210/3

n=70

So, three consecutive numbers are -

70, 71 and 72

$\underbrace\red{hope \: it \: helped \: u}$

Answer 2

$let \: \: \: 3 \: \: \: \: conscutive \: \: \: \: odd \: \: \: \: no \: \: \: \: be \\ \\ 2x + 1 \\ 2x + 3 \\ 2x + 5 \\ \\ \pink{hence} \\ \\ 2x + 1 + 2x + 3 + 2x + 5 = 213 \\ \\ 6x + 9 = 213 \\ \\ 6x = 213 - 9 \\ \\ 6x = 204 \\ \\ x = \frac{204}{6} \\ \\ x = 34 \\ \\ \pink{2x + 1 = 2 \times 34 + 1 = 68 + 1 = 69} \\ \\ \blue{2x + 3 = 2 \times 34 + 3 = 68 + 3 = 71} \\ \\ \green{2x + 5 = 2 \times 34 + 5 = 68 + 5 = 73}$

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