Question

The sum of three consecutive odd numbers is 105 what is the smallest out of the three

Answer 1

odd numbers are 2 apart
so they are n, n+2, n+4

the sum is 105
n+n+2+n+4=105
3n+6=105
minus 6 both sideds
3n=99
divide both sides by 3
n=33
n+2=35
n+4=37

33 is the smallest number
that's the smallest number

Answer 2

first odd no. is x 2nd is x+2 and 3rd is x+4
now add all three
3x+6=105
x=99/3
x=33
so the required consecutive odd no. was 33 , 35 and 37