The sum of three consecutive odd numbers is 111. find them
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Answered by
14
first integer= x
second integer= x+2
third integer= x+4
their sum is 111.
x+x+2+x+4= 111
3x+6= 111
3x= 111-6
3x= 105
x= 105/3
x= 35
first number= x= 35
second number= x+2= 35+2 = 37
third number=x+4= 35+4 = 39
required numbers are 35, 37 and 39.
hope it helps..☺☺
second integer= x+2
third integer= x+4
their sum is 111.
x+x+2+x+4= 111
3x+6= 111
3x= 111-6
3x= 105
x= 105/3
x= 35
first number= x= 35
second number= x+2= 35+2 = 37
third number=x+4= 35+4 = 39
required numbers are 35, 37 and 39.
hope it helps..☺☺
Answered by
4
let's consecutive no be
x+1+x+3+x+5=111
3X=102
X=34
therefore no 35 37 39
x+1+x+3+x+5=111
3X=102
X=34
therefore no 35 37 39
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