Question

The sum of three consecutive odd numbers is 147. find the numbers

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Answer 1

Answer: let x be first odd no. then consecutive no. are x+2, x+4

x+x+2+x+4=147

3x=147-6

x=141/3= 47

numbers r 47, 49, 51

Step-by-step explanation:

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Answer 2

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Let the first number be x

then second number = x+2

and third number = x + 4

According to the question,

x + (x+2) + (x+4) = 147

3x + 6 = 147

3x = 141

x = 141/3

x = 47

first number = x

⠀⠀⠀⠀⠀⠀⠀⠀= 47

second number = x + 2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 47 + 2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 49

third number = x + 4

⠀⠀ ⠀⠀⠀⠀⠀⠀= 47 + 4

⠀⠀⠀ ⠀⠀⠀⠀⠀= 51

Hence the required numbers are 47, 49 and 51.

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