Question

the sum of three consecutive odd numbers is 147. then the middle number is

Answer 1

Let the numbers be x, x+2, x+4.
Atq,
X + x+2 + x+4 = 147
3x + 6 = 147
3x= 147-6
X=141÷3
X= 47

Therefore I can find the middle non which would be 47+2=49.

Answer 2

Here is your solution

Let,
The first odd integer be:x

Then the second odd integer is:-
x+2

Then the third odd integer is:-
x+2+2=x+4

Sum of three consecutive odd numbers =147

A/q

(x)+(x+2)+(x+4)=147
3x+6=147
3x=147-6
3x=141
x=47
now

The first integer is: x=47

the second integer is: x+2=47+2 = 49

the third integer is: x+4=47+4=51

Middle number is 49

Hope it helps you