The sum of three consecutive odd numbers is 156. Find the prime number out of these numbers.? answer fast plz?
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Let those consecutive even numbers be a−2,a,a+2
Given,
(a−2)+a+(a+2)=156
⇒3a=156
⇒a=1563
⇒a=52
Smallest between a−2,a,a+2 is a−2
So a−2=52−2=50
Ans:- smallest of three even number sum up to give 156 is 50
Verification:- a−2+a+a+2=50+52+54=156
So our answer is correct
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