Question

the sum of three consecutive odd numbers is 21. find the numbers.​

Answer 1

Answer:

The numbers are 6,7,8

Step-by-step explanation:

Let the numbers be x, x+1 and x+2

x+x+1+x+2=21

3x+3=21

3x=18

x=6

x+1=6+1=7

x+2=6+2=8

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Answer 2

Given:

The sum of three consecutive odd numbers is 21.

Now,

Let the three consecutive odd numbers be

n, (n+2), and (n+4)

So,

According to the question,

n + (n+2) + (n+4) = 21

⇒ n + n + 2 + n + 4 = 21

⇒ 3n + 6 = 21

⇒ 3n = 21 - 6

[By taking 6 to RHS]

⇒ 3n = 15

⇒ n = 15 ÷ 3

[By transporting 3 to RHS]

⇒ n = 5

So,

The first number is n = 5,

Second number is (n+1) = 5+2 = 7

And the third number is (n+4) = 5+4 = 9

Hence,

The three consecutive odd numbers whose sum is 21 are,

5,7, and 9

- - -

Verification:

5 + 7 + 9

= 12 + 9

= 21

Hence,

Verified