Question

The sum of three consecutive odd numbers is 327, what is the smallest of these numbers?

Answer 1

HEY MATE HERE IS YOUR ANSWER

let the number be x,x+2,x+4

$x + x + 2 + x + 4 = 327 \\ 3x + 6 = 327 \\ 3x = 327 - 6 \\ 3x = 321 \\ x = 321 \div 3 \\ x = 107 \\ x + 2 = 107 + 2 = 109 \\ x + 4 = 107 + 4 = 111$

so the smallest number is 107

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Answer 2

let the number be x,x+2,x+4

x+x+2+x+4=327

3x+6=327

3x=327−6

3x=321

x=321÷3

x=107

x+2=107+2

x=109

x+4=107+4

x=111