The sum of three consecutive odd numbers is 57. the middle one is:
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middle number of those three consecutive odd numbers is 19
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Here is your solution
Let,
The first odd integer be:x
Then the second odd integer is:-
x+2
Then the third odd integer is:-
x+2+2=x+4
Sum of three consecutive odd numbers =51
A/q
(x)+(x+2)+(x+4)=57
3x+6=57
3x=57-6
3x=51
x=17
now
The first integer is: x=17
The second integer is: x+2=17+2 = 19
The third integer is: x+4=17+4=21
Middle term is 19
Hope it helps you
Let,
The first odd integer be:x
Then the second odd integer is:-
x+2
Then the third odd integer is:-
x+2+2=x+4
Sum of three consecutive odd numbers =51
A/q
(x)+(x+2)+(x+4)=57
3x+6=57
3x=57-6
3x=51
x=17
now
The first integer is: x=17
The second integer is: x+2=17+2 = 19
The third integer is: x+4=17+4=21
Middle term is 19
Hope it helps you
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