the sum of three consecutive odd numbers is 63 find the numbers
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Answered by
21
Let the numbers be
2x-1 , 2x + 1 , 2x+3
2x-1+2x+1+2x+3 = 63
6x = 63-3
x = 60/6
x = 10
so the numbers are
2x-1 = 2(10)-1 = 20-1 = 19
2x+1 = 2(10)+1 = 20+1 = 21
2x+3 = 2(10)+3 = 20+3 = 23
Hope it helps u :-)
2x-1 , 2x + 1 , 2x+3
2x-1+2x+1+2x+3 = 63
6x = 63-3
x = 60/6
x = 10
so the numbers are
2x-1 = 2(10)-1 = 20-1 = 19
2x+1 = 2(10)+1 = 20+1 = 21
2x+3 = 2(10)+3 = 20+3 = 23
Hope it helps u :-)
Answered by
9
Hiii. .....friend
The answer is here,
Let the numbers be 2x-1 , 2x+1 & 2x+3.
=> 2x-1+2x+1+2x+3 = 63.
=> 6x+3 =63.
=> 6x=60.
=> x=10.
So, The numbers are ,
=> 2 (10)-1 = 19.
=> 2 (10)+1 => 21.
=> 2 (10)+3 => 23.
:-)Hope it helps u.
The answer is here,
Let the numbers be 2x-1 , 2x+1 & 2x+3.
=> 2x-1+2x+1+2x+3 = 63.
=> 6x+3 =63.
=> 6x=60.
=> x=10.
So, The numbers are ,
=> 2 (10)-1 = 19.
=> 2 (10)+1 => 21.
=> 2 (10)+3 => 23.
:-)Hope it helps u.
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