Question

The sum of three consecutive odd numbers is 63. Find the numbers.

Answer 1

Here is your solution

Let,
The first odd integer be:x

Then the second odd integer is:-
x+2

Then the third odd integer is:-
x+2+2=x+4

Sum of three consecutive odd numbers =63

A/q

(x)+(x+2)+(x+4)=63
3x+6=63
3x=63-6
3x=57
x=19
now

The first integer is: x=19

the second integer is: x+2=19+2 = 21

the third integer is: x+4=19+4=23

Hope it helps you

Answer 2

Answer:

19, 21 and 23

Step-by-step explanation:

We know that consecutive odd number differ by 2 so,

Let the three consecutive odd numbers be x, ( x + 2 ) and ( x + 4 ) respectively.

We can derive the following equation by reading the question carefully,

x + ( x + 2 ) + ( x + 4 ) = 63

x + x + 2 + x + 4 = 63

3x + 6 = 63

3x = 63 - 6

3x = 57

x = 57 / 3

x = 19

Therefore we can calculate the consecutive odd numbers now:

First Consecutive Odd Number = 19

Second Consecutive Odd Number = 19 + 2 = 21

Third Consecutive Odd Number = 19 + 4 = 23