The sum of three consecutive odd numbers is 63. Find them. (Hint:-Let 2x+1 be the first odd numbers)
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Let the three consecutive odd numbers be (2x+1),(2x+3) and (2x+5).
According to the given condition,
we have
(2x+1)+(2x+3)+(2x+5) = 63
6x+9=63
6x=54 ...[By transposing 9 to RHS]
x=9
So,
three consecutive odd numbers are (2×9+1),(2×9+3) and (2×9+5) i.e., 19,21 and 23.
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