Question

The sum of three consecutive odd numbers is 69. Find the numbers.​

Answer 1

$\sf{Let \: first\: natural \: number \: be \: x}$

$\sf{Let \: second\: natural \: number \: be \: x + 1}$

:: $\sf{(x) + (x + 1) = 69}$

:: $\sf{ x + x + 1 = 69}$

:: $\sf{2x + 1 = 69}$

:: $\sf{2x = 69-1}$

:: $\sf{2x = 68}$

:: $\sf{x=}$ $\dfrac{68}{2}$

$\Rightarrow$ $\sf{x = 34}$

$\sf\blue{ ❍Hence,1st\: natural \: number=34}$

$\sf\blue{ ❍ 2nd\: natural \: number=34+1=35}$

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